Calculate the value admittance (Y) of the RLC
parallel circuit connected across 240volts/50Hz AC
supply and 8 Amp. Current is passed through it ? |
Answers
Answered by
2
Explanation:
The frequency of AC source =f=50Hz
Thus the impedance of the inductor, X
L
=ωL=(2πf)L=20πΩ
Resistance of the resistor =20Ω
Thus, the net impedance of the circuit =
X
L
2
+R
2
=65.94Ω
Thus, the current in the circuit =
X
V
=
65.94Ω
220V
=3.33A
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