Question

Calculate the value of 2(root3+root3+root3+...infinity)
(a) 1+root13
(6) 1-root13
(c) Both of these
(d) None of these

Answer 1

Error in question

proper question

$2( \sqrt{3 + \sqrt{3 + \sqrt{3 + ...} } }$

$Answer: both \: a \: and \: b$

Step-by-step explanation:

Procedure

• in this type of questions let the value of underroot be x

Solution

First find the value of root

$x = \sqrt{3 + \sqrt{3 + \sqrt{3 + ....} } }$

$x = \sqrt{3 + x}$

square both side

${x}^{2} = ( {\sqrt{3 + x})}^{2}$

from here

$x = \frac{1 + \sqrt{3} }{2}$

2x= 1+root3 or 1-root3