Math, asked by arifabelal2006, 1 month ago

Calculate the value of ‘a' for which (x+a) will be a factor of the polynomial x^3+ax^2-2x+a-12​

Answers

Answered by Innocentgirl58
1

Answer:

Hi there !!!

Given,

x - a is a factor of

x^{2} -ax^{2} +2x+a-1

we know,

x - a = 0

x = 0+a = a

Substitung the value of x as a,

we have,

(a)^3 - a(a)^2 + 2(a) + a - 1 =0

a^3 - a^3 + 2a + a - 1=0

3a - 1=0

3a =1

a = 1/3

Thus ,a = 1/3

Answered by srindhi1017
1

QUESTION:

Step-by-step explanation:

⇒  (x−a) is factor of x  

3

−ax  

2

+2x+a−1

⇒  Then, a is the zero of polynomial p(x)=x  

3

−ax  

2

+2x+a−1

⇒  p(x)=x  

3

−ax  

2

+2x+a−1

⇒  p(a)=(a)  

3

−a(a)  

2

+2(a)+a−1

⇒  0=a  

3

−a  

3

+2a+a−1

⇒  a  

3

−a  

3

+2a+a−1=0

⇒  3a−1=0

⇒  3a=1

∴   a=  

3/1  

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