Question

calculate the value of acceleration due to gravity on the surface of earth m e is equal to 6.0 into 10 power 24 kg R is equal to 6.4 into 10 power 6 metre G is equal to 6.67 into 10 power minus 11 NM square divided by kg square​

Answer 1

F = GMm / r^2

= (6.7 × 10^-11 × 6 × 10^24 × 60) / (6.4 × 10^6)^2

= 588.9 N

Answer 2

Answer:

Acceleration 'due to gravity' is also known as gravitational acceleration.

This gravitational force commonly calls on the body as its weight.

The acceleration 'due to gravity' on earth is actually $9.8 \mathrm{m} / \mathrm{s}^{\wedge} 2$

Given that:

'Radius' of the earth r $=6.4 \times 10^{6}$

'Mass' of the earth  $=6 \times 10^{24}$

Gravitational constant G  $=6.7 \times 10^{-11}$

$\mathrm{g}=\frac{\mathrm{GMm}}{\mathrm{R}^{2}}$

F is gravitational force- Newton

G is 'universal gravitational constant'  

M is mass of the body  

m is mass of the second body

R is distance b/w the two objects  

$=\frac{6.7 \times 10^{-11} \times 6 \times 10^{24} \times 60}{\left(6.4 \times 10^{6}\right)^{2}}$

$=\frac{2412 \times 10^{13}}{(6.4)^{2} \times 10^{12}}$

$=588.9 \mathrm{N}$

The value of acceleration due to gravity on the surface of the earth is 588.9 N