Question

calculate the value of acceleration due to gravity on the surface of the moon ?​

Answer 1

Explanation:

As the fact is accepted worldwide that the g in moon is 1/6 that of Earth.

And we also know that Eath g is 9.8 or say almost 10.(10 is easy to consider and calculate hence preffered ).

so 1/6 of 10 is 1.66666666667.

HOPE IT HELPS YOU AND PLZ MARK IT AS BRAINLIEST

Answer 2

$\huge\star\sf\underline\pink{Solution :-}$

$\sf\underline\red{Formula :-} \\ \\ {\sf{g = G \times \dfrac{M}{R^2} }} \\ \\ \sf{Here,} \\ \\ \sf{Gravitational\: constant (G) = 6.7 \times 10^{-11} Nm^2 /kg^2 } \\ \\ \sf{ Mass\:of\:the\:moon(M) = 7.4 \times 10^{22} kg} \\ \\ \sf{ Radius\:of\: the\:moon(R) = 1740 \:km} \\ \\ \longrightarrow\sf{1740 \times 1000 m} \\ \\ \\ \longrightarrow\sf{1.74 \times 10^6 }$

Now,

$\sf{Putting\: values\:into\: Formula:}$

$\\ \\ {\sf{g = \dfrac{6.7 \times 10^{-11} \times 7.4 \times 10^{22} }{(1.74 \times 10^6)^2} }}$

$\longrightarrow\sf{g = 1.63 \: m/s^2}$

Thus,

The acceleration due to gravity (g) on the surf6 of the moon is 1.63 m/s².