Question

Calculate the value of acceleration due to gravity on the surface of the moon.
(given : mass of the moon = 7.4 × 10^22 kg ; radius of moon = 1740 km ; G = 6.7 × 10^-11 Nm^2/kg^2)​

Answer 1

Answer:

acceleration due to gravity is the value of 9.8

Answer 2

Solution -

We have,

➝ Gravitational constant (G) = $\sf{6.7 \times 10^{-11}\: Nm^2/kg^2}$

➝ Mass of the moon (M) = $\sf{7.4 \times 10^{22}\: kg}$

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Similarly,

➝ Radius of the moon (R) = 1740 km

➝ R = 1740 × 1000 m

➝ R = 1.74 × 10⁶ m

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Now, the formula for calculating the acceleration due to gravity is :

$\large{\bf{\longmapsto{\boxed{\pink{g = G \times \dfrac{M}{R^2}}}}}}$

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Putting the values

$\tt\dashrightarrow{g = \dfrac{6.7 \times 10^{-11} \times 7.4 \times 10^{22}}{(1.74 \times 10^6)^2}}$

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$\tt\dashrightarrow{g = 1.63\: m/s^2}$

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Thus, the acceleration due to gravity (g), on the surface of the moon is 1.63 m/s².