Question

calculate the value of accleration due to gravitational force on the surface of the moon ,mass of moon = 7.4*10^22 kg radius of moon = 1740 km, G= 6.67*10^-11.

Answer 1

Answer:

Explanation:

M=7.4x10^22

R=1740

G=6.67x10^-11

g=GM/R^2=6.67x10^-11x1740/7.4x10^22

                 =1.62

Answer 2

Answer:

20.2 × 10¹⁹ N

Explanation:

Given :

Mass of earth = 6 × 10²⁴ kg

Mass of moon = 7.4 × 10²² kg

Distance between them = 3.84 × 10⁵ km = 3.84  × 10⁸ m

We have value of G = 6.7 × 10⁻¹¹ N m² kg⁻²

We have to find force :

We have :

F = G m₁ m₂ / r²

F = ( 6.7 × 10⁻¹¹ ) ( 6 × 10²⁴ ) ( 7.4 × 10²² ) / (  3.84 × 10⁸ )² N

F = 20.2 × 10¹⁹ N

Hence force exerted by the earth on the moon is 20.2 × 10¹⁹ N.