Physics, asked by mdshafiya432, 1 year ago

Calculate the value of bypass capacitor Cs in a common source amplifier, if g=1mA/V and the lower 3-dB frequency is 100Hz

Answers

Answered by franktheruler
12

The value of the bypass capacitor whose g and frequency values are given, is 10μF. This is because the capacitance value Cs is obtained by dividing the trans-conductance value by the frequency value.

This implies, Cs = (g/f) = (0.001/100) = 10^(-5) F = 10 * 10^(-6) F = 10μF.

 

Answered by aakankshasingla123
1

Answer:

Explanation:

Cs=g/f = 0.001/100 = 10uF

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