calculate the value of 'g' on moon .plzz send pic of whole solution with proper steps done by your own.... plzz share as soon as possible (class 9th) (chapter gravitation)
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On the surface of the moon (mass [M] =7.36*10^22 kg and radius R = 1.75*10^6 m ), the acceleration due to gravity at the surface of moon is :-
g
g
diauroseow5rs5:
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g on moon = (6.67 *10 raise to -11 ) * (7.36*10 raise to 22) the whole divided by (1.75*10 raise to 6) square = 1.6 ms raise to -2.
obviously. g on moon = 1/6 of g on earth nearly.
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Answered by
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Explanation:
The mass of moon =7 .35×10^22
The radius of moon=1.74×10^6
G=6.67×10^-11
g=6.67×10^-11×7.35×10^22/(1.74×10^6)^
=1.625m/s^2
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