Question

calculate the value of g on the surface of the moon given mass of moon 7.4×10^22 kg and radius of the moon 1.74×10^6m​

Answer 1

Given:-

→Mass of moon(Mₘ)=7.4×10²²kg

→Radius of moon(Rₘ)=1.74×10⁶m

To find:-

→Value of g(acceleration due to gravity) on the

surface of moon(gₘ)

Solution:-

→Value of G= 6.67×10⁻¹¹ Nm²/kg²

We know that:-

=>g=GM/R²

Thus:-

=>gₘ= GMₘ/R²ₘ

=>gₘ= 6.67×10⁻¹¹×7.4×10²²/(1.74×10×6)²

=>gₘ = (6.67×7.4/1.74×1.74)×(10⁻¹¹×10²²/10⁶×10⁶)

=>gₘ = 1.6m/s²

Thus,value of 'g' on the surface of moon

is 1.6m/s².

Some Extra Information:-

•Value of g on earth's surface is 9.8m/s².

•Value of g on the surface of moon is approximately 1/6 of the value of g on the surface of earth.

∴gₘ= gₑ/6

•The value of g is more at the equator than the poles.

•The value of g decreases with height.

•Value of g is zero at the centre of the earth.