Question

Calculate the value of gravitational acceleration at moon surface given mass of moon Mn= 74×10’23 kg Radius of moon Rm= 1700km​

Answer 1

Answer:

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Explanation:

answer is shown above.

g=1.63 m/s²

Given that,

Mass of the moon, M=7.4\times 10^{22}\ kgM=7.4×10²² kg

Radius of the moon, R=1740\ km=1740\times 10^3\ mR=1740 km=1740×10³ m

Gravitational constant, G=6.7\times 10^{-11}\ Nm^2/kg^2G=6.7×10

−11

Nm

2

/kg

2

The acceleration due to gravity on the surface of Moon is given by :

g=\dfrac{GM}{R^2}g=

R

2

GM

g=\dfrac{6.7\times 10^{-11}\times 7.4\times 10^{22}}{(1740\times 10^3)^2}g=

(1740×10

3

)

2

6.7×10

−11

×7.4×10

22

g=1.63\ m/s^2g=1.63 m/s

2

So, the acceleration due to gravity on the surface of moon is 1.63\ m/s^21.63 m/s

2

. Hence, this is the required solution.

Answer 2

Answer:

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