calculate the value of j.(2i-3j+k) and(2i-j).(3i+k)
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Answer:
(i).(0i+j+0k). (2i-3j+k)
=0×2+1×-3+0×1
=-3
(ii). (2i-j+0k). (3i+0j+k)
=2×3+-1×0+0×1
=6
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