calculate the value of m&n if (m+1)^2+(n+1)^2=0
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Answered by
1
This system of equation is of the form
a
1
x+b
1
y+c
1
=0
a
2
x+b
2
y+c
2
=0
where a
1
=2m−1,b
1
=3,c
1
=−5
and a
2
=3,b
2
=n−1 and c
2
=−2
For infinitely many solutions, we must have
a
2
a
1
=
b
2
b
1
=
c
2
c
1
The given system of equations will have infinite number of solutions, if
3
2m−1
=
n−1
3
=
−2
−5
⇒
3
2m−1
=
n−1
3
=
2
5
⇒
3
2m−1
=
2
5
and
n−1
3
=
2
5
⇒4m−2=15 and 6=5n−5
⇒4m=17 and 5n=11
⇒m=
4
17
and n=
5
11
Hence, the given system of equations will have infinite number of solutions, if m=
4
17
and n=
5
11
.
Answered by
1
Answer:
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