Question

calculate the value of neutral axis constant for m20 grade concrete and mild steel reinforced in wsm​

Answer 1

Answer:

kindly refer to the attachment....

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Explanation:

Answer 2

Answer:

Explanation:

M20 grade of concrete

• M20 grade of concrete is a minimum nominal mix of concrete which is used in RCC work of construction of building structural member like compressive member footing, foundation and column and flexural members like beam and slab.

• M20 concrete of grade represents M stands for concrete mix design and 20 numerical figure is their characteristics of compressive strength gain in 28 days after casting and proper curing. Their fck value or characteristics of compressive strength is 20 N/mm2.

M20 grade of concrete mix ratio

• M20 concrete mix ratio:- M20 concrete mix ratio is 1:1.5:3, made of a mixture of cement, sand, and aggregate in which one part is cement, 1.5 part is sand and 3 part is aggregate or stone.
• It means 1 bag of cement mixed with 1.5 bags of sand and three bags of aggregate to make a concrete mix of M20 grade concrete.
• Calculate the quantity of cement sand and aggregate in 1m3 of m20 grade of concrete

• As we know that during concreting when we place wet concrete it gets hardened after a certain standard time of 30 minute to 10 hours and the voids of concrete is completely evaporated so there is a decrease in their volume and their volume is decrease by about 54% means dry volume of concrete is increased by 54%

We have given the Volume of wet concrete = 1m3

And we know that the dry volume of concrete is 1.54 times of wet concrete volume

So dry volume of concrete = 1.54 m3

It means 1.54 cubic meters of the dry composition of cement sand and aggregate is required for the casting of wet concrete 1 cubic meter when it is added with water.

M20 concrete ratio = 1 : 1.5 : 3

Sum of grade of concrete ratio = 1+1.5+3 =5.5

1) Volume of aggregate = (3/5.5)×1.54 m3

Volume of aggregate = 0.84 m3

1m3 = 35.32 cft

Volume of aggregate = 0.84×35.32 cft

Volume of aggregate = 29.67 cft

2) volume of sand = (1.5/5.5)×1.54 m3

Volume of sand = 0.42 m3

1 m 3 = 35.32 cft

Volume of sand in cft = 0.42×35.32 cft

Volume of sand in cft = 14.83 cft

3) Volume of cement =( 1/5.5)×1.54 m3

Volume of cement = 0.28 m3

Density of cement = 1440 Kg/m3

Weight of cement in Kg = 1440×0.28 Kg

Weight of cement = 403 kg

Weight of one bag cement = 50 kg

Bag of cement = 403/50 =8 bag cement