Question

Calculate the value of orbital velocity for an artificial

satellite of earth orbiting at a height of 1000 km (Mass

of the earth = 6×1024 kg radius of the earth = 6400

km).​

Answer 1

Answer:

Here, h=1000 km=1000×10

3

m=10

6

m

r=R+h=6.38×10

6

+10

6

=7.38×10

6

m

Orbital speed,

v

0

=

R+h

GM

=

7.38×10

6

6.67×10

−11

×6×10

24

=7364m s

−1

Time period,

T=

v

0

2πr

=

7.364×10

3

2×(22/7)×(7.38×10

6

)

=6297

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