Question

calculate the value of proptionality constant k for 1 mole of a gas which occupies 22.4 L of volume under the given conditions of temperature and pressure

Answer 1

if n=1 V=22.4L
v=kn
k=v/n=22.4 L mol^-1

Answer 2

Here is your answer.
STP (Standard Temperature and Pressure) or NTP, where T = 273K and p = 1 atm, 22.4L of each gas has NA = 6.023 x 10^23molecules. In other words, one mole of any gas under STP conditions occupies 22.4L volume.

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