Question

calculate the value of Resistance needed to the convert or moving coil galvanometer of 60 ohm into ammeter of range 5A which give full scale deflection of current of 50 and into voltmeter of range 0-50V​

Answer 1

The resistance of $0.6061\Omega$ in parallel and  $940\Omega$in series is connected to moving coil galvanometer

Explanation:

In question given, full scale deflection of current of 50 m A not 50.

Further explanation.

Given galvanometer  resistance, G =60 ohm.

Ammeter current,i = 5 A.

I = 50 m A.

The voltage, V =50 V.  

To calculate the resistance, use the formula

  $R=\frac{V}{I} -G$

Substitute the values, we get

$R=\frac{50V}{50\times10^-^3A}-60\Omega$

$R=940\Omega$.

Now formula to get shut resistance,

$S=\frac{GI}{i-I}$

substitute the values, we get

$S=\frac{60\Omega\times50\times10^-^3A}{5A-50\times10^-^3A}$

$S=0.6061\Omega$.

Thus, the resistance of $0.6061\Omega$ in parallel and  $940\Omega$in series is connected to moving coil galvanometer.

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