Question

calculate the value of shunt to convert galvanometer of resistance 100Ω gives full scale deflection for 3mA into an ammeter 0-6A​

Answer 1

Explanation:

I=I

g

+I

s

(I−I

g

)R

s

=I

g

R

g

Given,

I=10A

I

g

=10mA=0.010A

R

g

=100Ω

Substituting the values,

(10−0.010)R

s

=0.010×100

⇒R

s

=

9.99

1

=0.1

Answer 2

Explanation:

I=I

g

+I

s

(I−I

g

)R

s

=I

g

R

g

Given,

I=10A

I

g

=10mA=0.010A

R

g

=100Ω

Substituting the values,

(10−0.010)R

s

=0.010×100

⇒R

s

=

9.99

1

=0.1