Question

Calculate the value of spin magnetic moment for mn2+ ion.

Answer 1

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Answer...

No of free electrons in $Mn^{2+}$ atom , n = 5

Spin magnetic moment ,

μ = √n(n + 2)

= √5(5 + 2)

= √5(7)

= 5.91 BM

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Answer 2

$\mathbb{ \ \ ANSWER \: \: }$

No of free electrons in Mn²+ atom , n = 5

Spin magnetic moment ,

μ = √n(n + 2)

= √5(5 + 2)

= √5(7)

= 5.91 BM