Question

calculate the value of stress in a wire of steel having radius of 2mm when 10KN of force acts on it.​

Answer 1

Radius of the wire, R = 2mm = 2×10^-3m

Area of the wire, A = πR² = 3.14 × 4 × 10^-6 = 1.256 × 10^-5

Stress = (Force Applied)÷(Area)

= (10×10³)÷(1.256×10^-5)

= 7.96 × 10^8 N/m2

Answer 2

The value of stress in the wire is $S=7.95\times 10^8\ Pa$.

Explanation:

It is given that,

Radius of the wire, r = 2 mm = 0.002 m

Force acting on the wire, $F=10\ kN=10^4\ N$

We need to find the value of stress in the wire. The force acting per unit area on a wire is given by :

$S=\dfrac{F}{A}$

$S=\dfrac{F}{\pi r^2}$

$S=\dfrac{10^4}{\pi (0.002)^2}$

$S=7.95\times 10^8\ Pa$

So, the value of stress in the wire is $S=7.95\times 10^8\ Pa$. Hence, this is the required solution.

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