Question

calculate the value of the acceleration due to gravity on the surface of moon =7.4×10²²kg.​

Answer 1

Answer:

g=1.63 m/s2

Explanation:

Given that,

Mass of the moon, M=7.4\times 10^{22}\ kgM=7.4×1022 kg

Radius of the moon, R=1740\ km=1740\times 10^3\ mR=1740 km=1740×103 m

Gravitational constant, G=6.7\times 10^{-11}\ Nm^2/kg^2G=6.7×10−11 Nm2/kg2

The acceleration due to gravity on the surface of Moon is given by :

g=\dfrac{GM}{R^2}g=R2GM

g=\dfrac{6.7\times 10^{-11}\times 7.4\times 10^{22}}{(1740\times 10^3)^2}g=(1740×103)26.7×10−11×7.4×1022

g=1.63\ m/s^2g=1.63 m/s2

So, the acceleration due to gravity on the surface of moon is 1.63\ m/s^21.63 m/s2 . Hence, this is the required solution.

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