Calculate the value of the additional capacitor
which may be joined suitably to the capacitor C
that would make the power factor of the circuit
unity.
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Answered by
5
Answer:
(a)The phase difference between current and voltage ϕ is given by
tanϕ=RXC−XL
XC=ωC1=500Ω
XL=ωL=100Ω
R=400Ω
Thus tanϕ=400400=1
⟹ϕ=45∘
(b) Power factor is given by cosϕ=1
⟹ϕ=0∘
⟹tanϕ=0
⟹XC=XL=100Ω
⟹C=10μF
Hence an 8μF capacitor need to be connected in parallel with the given capacitor.
(a)The phase difference between current and voltage ϕ is given by
tanϕ=RXC−XL
XC=ωC1=500Ω
XL=ωL=100Ω
R=400Ω
Thus tanϕ=400400=1
⟹ϕ=45∘
(b) Power factor is given by cosϕ=1
⟹ϕ=0∘
⟹tanϕ=0
⟹XC=XL=100Ω
⟹C=10μF
Hence an 8μF capacitor need to be connected in parallel with the given capacitor.
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1
Answer:
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