Calculate the value of the electric field when the feid point is located at 3cm from the point Charge. The Change of the point is 4 nc
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q= 0.83nc
Explanation:
r= V/E=15/30=0.5
q=9×1091×0.5m
v=4π
q=0.83×10-9c
q= 0.83nc
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