Math, asked by Anonymous, 5 months ago

Calculate the value of the following

Attachments:

Answers

Answered by suzanejazinth
1

Answer:

a)-\frac{5}{7}(-\frac{28}{15}+1\frac{2}{3}) =-\frac{5}{7}(-\frac{28}{15}+\frac{5}{3})\\=-\frac{5}{7}(\frac{-28+25}{15}) = -\frac{5}{7}(\frac{-3}{15}) = \frac{-5}{7}(\frac{-1}{5})\\=\frac{5}{35} = \frac{1}{7}\\\\b)[-(\frac{1}{2})^{2}-(-\frac{1}{3})] + (\frac{1}{4}-\frac{1}{3}) = [-\frac{1}{4}+\frac{1}{3}]+[\frac{1}{4}-\frac{1}{3}] = 0

Similar questions