Question

Calculate the value of the magnetic field induction at the center of a loop of wire of radius 0.06m and carries a current of 10 A ? plz guys fastly answer this question it is required​

Answer 1

Given :

➳ Radius of loop = 0.06m

➳ Current flow = 10A

To Find :

➾ Magnetic field induction at the center of a loop.

Formula :

➠ Magnetic field at the centre of a circular loop is given by

$\bigstar\:\underline{\boxed{\bf{\red{B=\dfrac{\mu_o I}{2R}}}}}$

where,

◕ B denotes magnetic field

◕ I denotes current

◕ R denotes radius

◕ $\mu_o$ denotes permeability of free space

Calculation :

$\dashrightarrow\sf\:B=\dfrac{\mu_o I}{2R}\\ \\ \dashrightarrow\sf\:B=\dfrac{(4\pi\times 10^{-7})\times 10}{2\times 0.06}\\ \\ \dashrightarrow\underline{\boxed{\bf{\purple{B=3.33\pi\times 10^{-5}\:T}}}}\:\orange{\bigstar}$

Answer 2

$\bigstar$ $\sf{\purple{\underline{\underline{\red{To\:Find:-}}}}}$

• The value of Magnetic field induction at the center of a loop of the wire .

$\bigstar$ $\sf{\red{\underline{\underline{\purple{SOLUTION:-}}}}}$

☞ FORMULA :-

• Magnetic field induction at the center of a loop of wire ,

$\checkmark\:\tt{\red{\boxed{\:B\:=\:{\dfrac{\mu_o\:\times\:I}{2\:R}}\:}}}$

Where,

• B = magnitude of Magnetic field induction

• $\tt{\mu_o\:=\:4{\pi}\:\times\:10^{-7}}$

• I = current flowing through the wire

• R = Radius of the current carrying loop

☞ GIVEN :-

• I = 10 A .
• R = 0.06 m .

☞ Now, Calculate “ B ” from the above formula

$\tt{\implies\:B\:=\:{\dfrac{(4\:{\pi}\:\times\:10^{-7})\:\times\:10\:}{2\:\times\:0.06}}\:}$

$\tt{\implies\:B\:=\:3.33{\pi}\:\times\:10^{-5}\:T}$

$\bigstar\:\underline{\boxed{\bf{\red{Required\:Answer\::\:B\:=\:3.33\:{\pi}\:\times\:10^{-5}\:T\:}}}}$