Question

calculate the value of two equal charges if they repel each other with a force of 0.1 Newton when situated 50 cm apart in vacuum.what would be the distance between them if they are placed in an insulated medium of dielectric constant 10?​

Answer 1

i) Q1 = Q1 =  Q = 1.67 uC

ii) r = 15.8cm  

Explanation:

As, the magnitude of both charges equal so,  Q1 = Q1 =  Q

r = 50 cm

F = 0.1 N

According to Coulomb’s law  

F = K Q^2/r^2     (in Vaccum)

By putting the value in above equation  and solving for Q, we get  

Q = 1.67 uC

Now, for second part the Coulomb’s law will be  

F = K Q^2/E r^2      

Solving for r,

r = 15.8 cm  

Answer 2

Answer:0.1m

Force(f) =