calculate the value of two equal charges if they repel each other with a force of 0.1 Newton when situated 50 cm apart in vacuum.what would be the distance between them if they are placed in an insulated medium of dielectric constant 10?
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i) Q1 = Q1 = Q = 1.67 uC
ii) r = 15.8cm
Explanation:
As, the magnitude of both charges equal so, Q1 = Q1 = Q
r = 50 cm
F = 0.1 N
According to Coulomb’s law
F = K Q^2/r^2 (in Vaccum)
By putting the value in above equation and solving for Q, we get
Q = 1.67 uC
Now, for second part the Coulomb’s law will be
F = K Q^2/E r^2
Solving for r,
r = 15.8 cm
Answered by
0
Answer:0.1m
Force(f) =
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