calculate the value of x
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In triangle ABC,
angle ABC = 35 degree
therefore angle BAC = 35 degree (ABC is an isosceles triangle)
angle ABC + angle BAC + angle ACB = 180 degree
= 35 degree + 35 degree + angle ACB = 180 degree
= angle ACB = 180 degree - 35 degree + 35 degree
= angle ACB = 180 degree - 70 degree
= 110 degree
Angle ACB + angle ACD = 180 degree
Angle ACD = 180 degree - angle ACB
= 180 degree - 110 degree
= 70 degree
Since angle ACD = 70 degree
Therefore angle CAD is also 70 degree (ACD is an isosceles triangle )
angle ACD + angle CAD + angle ADC = 180 degree
= 70 degree + 70 degree + angle ADC= 180 degree
angle ADC = 180 degree - 70 degree + 70 degree
= 180 degree - 140 degree = 40 degree
Therefore x = 40 degree
HOPE IT HELPS YOU !!!!!
angle ABC = 35 degree
therefore angle BAC = 35 degree (ABC is an isosceles triangle)
angle ABC + angle BAC + angle ACB = 180 degree
= 35 degree + 35 degree + angle ACB = 180 degree
= angle ACB = 180 degree - 35 degree + 35 degree
= angle ACB = 180 degree - 70 degree
= 110 degree
Angle ACB + angle ACD = 180 degree
Angle ACD = 180 degree - angle ACB
= 180 degree - 110 degree
= 70 degree
Since angle ACD = 70 degree
Therefore angle CAD is also 70 degree (ACD is an isosceles triangle )
angle ACD + angle CAD + angle ADC = 180 degree
= 70 degree + 70 degree + angle ADC= 180 degree
angle ADC = 180 degree - 70 degree + 70 degree
= 180 degree - 140 degree = 40 degree
Therefore x = 40 degree
HOPE IT HELPS YOU !!!!!
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