Question

calculate the value of x in each of the following figures​

Answer 1

Answer:

sorry I don't know answer

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Answer 2

$\huge\color{blue}{\mid{\fbox{\tt{Solution:-}}\mid}}$

IN THE GIVEN FIGURE,

∠ACD is 115°

∠ABC is x °

∠ BAC is 60° (VERTICALLY OPPOSITE ANGLES)

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NOW,

Sum of linear pair =180°

THE MEASURE OF ∠ACB IS :-

180-115 (linear pair)

=65°

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NOW,

WE HAVE ∠BAC as 60°

AND ∠ACB as 65°

SUM OF ALL ANGLES IN A TRIANGLE =180°

SO,

WE GET THE EQUATION AS :-

65°+60°+x=180°

125+x=180°

x=180°-125°

x=55°

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$\small\fbox\pink{Hence,the\:value\:of\:x\:is\:55°}$

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$\small\boxed{\fcolorbox{black}{blue}{Extra\:Info}}$

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• A triangle has three sides, three angles, and three vertices.
• The sum of all internal angles of a triangle is always equal to 180°. This is called the angle sum property of a triangle.
• The sum of the length of any two sides of a triangle is greater than the length of the third side.

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