Question

calculate the value of x in given expression (11/9)^3 × (9/11)^6=(11/9)^2x‐1​

Answer 1

Answer:

The answer is $-1$

Step-by-step explanation:

  $\displaystyle \left(\frac{11}{9}\right)^3\times \left(\frac{9}{11}\right)^6=\left(\frac{11}{9}\right)^{2x-1}$ given

$\Rightarrow \displaystyle \left(\frac{11}{9}\right)^3\times \left(\frac{11}{9}\right)^{-6}=\left(\frac{11}{9}\right)^{2x-1}$ since $\displaystyle (\frac{a}{b})^{n}=(\frac{b}{a})^{-n}$

$\Rightarrow \displaystyle \left(\frac{11}{9}\right)^{3-6}=\left(\frac{11}{9}\right)^{2x-1}$since $a^m\times a^n=a^{m+n}$

$\Rightarrow \displaystyle \left(\frac{11}{9}\right)^{-3}=\left(\frac{11}{9}\right)^{2x-1}$

$\Rightarrow -3=2x-1$ since $a^x=a^y\Rightarrow x=y$

$\Rightarrow 2x=-3+1\\\Rightarrow 2x=-2\\\Rightarrow x=-1$

Answer 2

Answer:

THE ANSWER IS -1.

Step-by-step explanation:

REFER THE ATTACHMENT.

HOPE IT HELPES YOU DEAR AS I WASNT ABLE TO ANSWER ONE OF YOUR QUESTION LAST TIME.