Question

calculate the value of ∆x.∆v for an electron. and using mass of electron​

Answer 1

Explanation:

Δx×m×ΔV=

4π

h

Δx= uncertainty in the position

m=9.1×10

−31

kg= mass of electron

ΔV=300×

100

0.001

=0.003m/s

uncertainty in the velocity

h=6.62×10

−36

Js= Planck's constant

Substitute values in the above formula

Δx×9.1×10

−31

×0.003=

4×3.1416

6.62×10

−34

Δx=1.92×10

−2

m

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