calculate the value of x° in the given figure
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X=160 IS YOUR ANSWER FOR THIS QUESTION
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in triangle ABC
A+B+ ACB = 180⁰
30⁰ + 40⁰ + ACB = 180⁰
70⁰ + ACB =180⁰
ACB = 180⁰-70⁰
angle ACB = 110⁰
ACB + ACD = 180⁰
110⁰ + ACD = 180⁰
ACD = 180⁰- 110⁰
ACD = 70⁰
x = 70⁰+50⁰(exterior angle property)
x = 120⁰
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