Question

Calculate the value of xyz if a=b2x, c2y and c=a2z

Answer 1

Answer:

Given , a = b2x ................ (i)

b = c2y ................ (ii)

c= a2z ................. (iii)

Substituting the value of b from (ii) in (i) , we get ,

a = (c^2y)^2x = c^4xy.........(iv)

Substituting the value of c from (iii) in (iv) , we get ,

a = (a^2z)^4xy = a^8xyz

=) a = a^8xyz

=) a^1 = a^8xyz

Therefore , xyz = 1/8 .