Calculate the values of :
i) j cap . (2i cap - 3 j cap + k cap)
ii) (2 i cap=j cap) . (3 i cap +k cap)
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Ans: Jcap .(2icap-3jcap+kcap)
(0icap + jcap + 0kcap )(2icap-3jcap+kcao)
0-3+0 = 3
(2icap-jcap)(3icap+kcap) =6+0+0 =6
(0icap + jcap + 0kcap )(2icap-3jcap+kcao)
0-3+0 = 3
(2icap-jcap)(3icap+kcap) =6+0+0 =6
tokaians:
how ??
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