Calculate the vapour density of a gas, 12.8g of which
occupies 10L at a pressure of 750 mm at 27°C.
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Answer:
V.D. = 15.92
Explanation:
We know :
Vapour density ( V.D. ) = W / 2 × ( R T / P V )
We have given :
W = 12.8 g
T = 27 C = 27 + 273 K = 300 K
P = 750 / 760 atm
V = 10 L
Value of R = 0.081 L-atm mol⁻¹ K⁻¹
Putting values we get :
V.D. = ( 12.8 × 0.082 × 300 ) / ( 750 / 760 × 10 × 2 )
V.D. = ( 6.4 × 8.2 ) ( 15 / 76 × 10 )
V.D. = 15.92
Hence we get required answer.
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