Chemistry, asked by Anonymous, 11 months ago

Calculate the vapour density of a gas, 12.8g of which
occupies 10L at a pressure of 750 mm at 27°C. ​

Answers

Answered by niharikam54
0

Answer:

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Attachments:
Answered by BendingReality
6

Answer:

V.D. = 15.92

Explanation:

We know :

Vapour density ( V.D. ) = W / 2 × ( R T / P V )

We have given :

W = 12.8 g

T = 27 C = 27 + 273 K = 300 K

P = 750 / 760 atm

V = 10 L

Value of R = 0.081 L-atm mol⁻¹ K⁻¹

Putting values we get :

V.D. = ( 12.8 × 0.082 × 300 ) / ( 750 / 760 × 10 × 2 )

V.D. = ( 6.4 × 8.2 ) ( 15 / 76 × 10 )

V.D. = 15.92

Hence we get required answer.

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