Question

Calculate the vapour density of a gas whose 5g occupies a volume of 2.8 L at STP

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Answer 1

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Answer 2

Answer:

The vapour density of the gas is 20.

Explanation:

Given :

5g occupies a volume of 2.8 L at STP

To find :

the vapour density of the gas

Solution :

Let the molecular weight of the gas be 'x'.

1 mole of the gas occupies 22.4 L at STP.

i.e., x g of the gas occupies 22.4 L at STP.

It's given that 5 g of the gas occupies a volume of 2.8 L at STP.

First, let's find the value of x.

$\tt x = 22.4 \times \dfrac{5}{2.8} \\\\ \tt x = 8 \times 5 \\\\ \tt x= 40 g$

Therefore, the molecular weight of the gas is 40 g.

Vapour density = Molecular weight/2

So, VD = 40/2

VD = 20

The vapour density of the gas is 20.