Question

calculate the vapour density of butane gas when [C=12;H =1​

Answer 1

Answer:

your answer is 22.4×10-³m3

Explanation:

This means 1 mole of butane has a volume of 22.4dm3 at STP.

∴v=22.4dm3.

=22.4×103cm3.

=22.4×10−3m3.

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Answer 2

Answer:

butane means C4H10

molecular mass of butane = C=12*4=48

                          = H=1*10=10

                           =48+10=58gm

we know, Vapour density= molecular mass/2

                                          =58/2

                                          =29gm

Explanation: