calculate the vapour pressure 15% w/w aqueous solution of urea at 298 k temperature. the vapour pressure of water is 0.025 bar
Answers
Answered by
1
Answer:
the answer is 23.14mm.
Explanation:
Mass of urea = 5 g
Mass of water = (100-5)
= 95 g
No. of moles of urea = 5/ 60
= 0.083
No. of moles of water = 95/ 18
=5.278
Total number of moles = 5.278 + 0.083
= 5.361
Mole fraction of solvent = 5.278/ 5.361
Ps = Mole fraction of solvent × Po
= 5.278 / 5.361 × 23.5
= 23.14mm
Similar questions