Question

calculate the vapour pressure of a solution containing 9 grms of glucose in 162 gr of water at 293k .the vapour pressure of a water at 293k is a17.535 mm Hg.​

Answer 1

Answer:

The molar masses of glucose and water are 180 g/mol and 18 g/mol respectively.

Number of moles of glucose =

180

25

=0.139

Number of moles of water =

18

450

=25

Mole fraction of glucose =

0.139+25

0.139

=0.0055

Vapour pressure lowering is directly proportional to the mole fraction

P

0

P

0

−P

=X

17.535

17.535−P

=0.0055

P=17.438

Hence, the vapour pressure of a solution is 17.438 mm Hg.

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