Calculate the vapour pressure of an
aqueous solution of 1.0 molal glucose solution at 100°C.
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Answer:
Molality = w/m×W×1000
where.w= mass of solute in grams;
W= mass of solvent in grams
1.0=w/m×W×1000
(Or) w/m×W=1.0/1000=0.001
Applying Raoult's law for dilute solution
P
0
−P
s
=
m×W
w
×M(M=18)
760
760−P
s
=0.001×18(P
0
=760mmat100
o
C)
or P
s
=760−760×0.001×18
=760−13.68
=746.32mm
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