Question

calculate the vapour pressure of aqueous 0.1 m glucose solution at 300K temperature,the vapour pressure of water is 0.03 bar at 300 K temperature

Answer 1

Hey dear,

● Answer -
P(soln) = 0.02998 bar

● Explaination -
Gluocse solutiion is 0.1 molal.
n(glucose) = 0.1 mol
W(water) = 1 L = 1 kg
n(water) = 1000/18 = 55.56 mol

Mole fraction of water -
X(water) = 55.56 / (55.56 + 0.1)
X(water) = 0.9998

Vapor pressure of glucose solution is calculated by -
P(soln) = P°(water).X(water)
P(soln) = 0.03 × 0.9998
P(soln) = 0.02998 bar

Vapour pressure of glucose soln is 0.02998 bar.

Hope this helped...

Answer 2

Answer:

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Explanation:

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