Calculate the Vapour pressure of (CCL)4 at 25°C.If the Boiling point of (CCL)4 is 75°C and Enthalpy of Vapourisation is. 31 KJ/mol ?
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Answer:Correct option is
A
141.93 mm
P
0
=143
V=100ml
P
0
P
0
−P
=
n
A
n
B
n
B
=
65
0.5
mass=V×d=100×1.58=158
n
A
=
154
158
P
0
P
0
−P
=
65
0.5
×
158
154
=0.007
143−P=.007×143=1.07
⇒P=143−1.07=141.93
Explanation:
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