Question

Calculate the vapour pressure of the solution at 100°C containing 3gms of cane sugar
in 33 gms of water. (molecular weight of sugar = 342]
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Answer 1

Answer:

756.90 mm

Explanation:

Vapour pressure of pure water (solvent) at 100°C, p0 = 760 mm. Vapour pressure of solution, p = ? Wt. of solvent , W = 33g Wt. of solute , w = 3g Mol. wt. of water (H2O), M = 18 Mol. wt. of sugar (C12H22O11), m = 12 x 12 + 22 x 1 + 11 x 16 = 342 According to Raoult’s law , = 760 – 3.19 = 756.90mmRead more on Sarthaks.com - https://www.sarthaks.com/205005/calculate-the-vapour-pressure-of-solution-at-1000c-containing-cane-sugar-33g-water-at-wt-12