Question

Calculate the vapour pressure of the solution. When the mole fraction of the

solute is 0.5, the vapour pressure of the pure solvent is 0.6 atm.​

Answer 1

Answer:

p

0

△p

=x

2

p

0

△p

=

n

1

n

2

=

M

2

×m

1

m

2

×M

1

=

1000

m×m

1

p

0

△p

=

1000

0.5×18

=0.009

p

0

p

0

−p

=0.009

[m=molarity=

M

2

m

2

×

m

1

1000

119.6

119.6−p

=009

19.6−p=1.0764