Question

Calculate the velocity and kinetic energy of a neutron having de-Broglie wave length 1Å.

Answer 1

Answer:

Neutron m=1.67×10−27 kg

l=ph  ⇒P=λh  =1×10−1066×10−34 kg m/s

⇒P=6.6×10−24 kg m/s

energy  E=2mP2=2×1.67×10−276.6×6.6×10−48 joule

=3.34(6.6)2×10−21×1.6×10−191 ev

E = 0.8 ev

Answer 2

Answer:

K.E=.8ev

v=1.23m/s

Explanation:

m= 1.67×10-²⁷kg

I=ph , p=h/lambda

p= 6.626×10-³⁴/10-¹⁰×1

p=6.626×10-²⁴kg m/s

E= p²/2m

after calculation

E=.8ev

this is required answer

K.E= 1/2mv²

v²= 1.6×.8×2×10-¹⁹/1.67×10-²⁷

v²=1.53×10⁸

v= 1.23×10⁴m/s

this is the velocity