Question

Calculate the velocity of a motor care if it accelerated at 1,2m/s for 8 seconds from 25km/h

Answer 1

CORRECT QUESTION :–

• Calculate the velocity of a motor car if it accelerated at 1.2m/s² for 8 seconds from 25km/h.

ANSWER :–

GIVEN :–

• Acceleration(a) = 1.2 m/s

• Initial velocity(u) = 25 km/hr = 25 × 5/18 m/s = 125/18 m/s

• Time = 8 sec.

TO FIND :–

• Final velocity(v) = ?

SOLUTION :–

• We know that –

⇒ v = u + at

• Put the values –

⇒ v = 125/18 + (1.2)(8)

⇒ v = 125/18 + 9.6

⇒ v = 6.9 + 9.6

⇒ v = 16.5 m/s

⇒ v = 16.5 × (18/5) km/h

⇒ v = 59.4 km/h

Answer 2

${\large{\sf{\underline{Correct \; Question}}}}$

★ Calculate the velocity of a motor care if it accelerated at 1.2m/s for 8 seconds from 25 km/h.

${\large{\sf{\underline{Given \; that}}}}$

★ Acceleration of motor cycle = 1.2 m/s

★ Time taken to be accelerated = 8 seconds.

★ Initial velocity = 25 km/h

${\large{\sf{\underline{To \; find}}}}$

★ Velocity.

${\large{\sf{\underline{Solution}}}}$

★ Velocity = 16.5 m/s

${\large{\sf{\underline{Using \; concepts}}}}$

★ Conversion of km/h into m/s

★ Newton's law of motion (v = u+at)

${\large{\sf{\underline{Full \; Solution}}}}$

~ Firstly let us convert km/h into m/s

↝ 25 km/h into m/s

↝ 25 × 5/18

↝ 125/18

↝ 6.9 m/s

${\frak{\underline{Henceforth, \: 6.9 \: m/s \: is \: initial \: velocity}}}$

~ Now let's put the values according to the formula.

↝ v = u+at

↝ v = 6.9+(1.2)(8)

↝ v = 6.9 + 1.2 × 8

↝ v = 6.9 + 9.6

↝ v = 16.5 m/s