Chemistry, asked by farah55, 10 months ago

Calculate the velocity of an electron
placed in the third orbit of hydrogen atom. Also caculate no. of revolution per second that this electron makes around the nucleus​

Answers

Answered by antiochus
0

Answer:

μn=\sqrt{\frac{ze^{2} }{mr_{n} } )}

Radius of 3rd orbit is=r_{1} *n^{2}

                                  =0.529*10^{-8} *9cm

μn=\sqrt{(\frac{1*(4.083*10^{-10} )^{2} }{(9.108*10^{-28}*0.529*10^{-8}*9  }) }

μn=7.29*10^{7} cmsec^{-1}

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