Chemistry, asked by farah55, 1 year ago

Calculate the velocity of an electron
placed in the third orbit of hydrogen atom. Also caculate no. of revolution per second that this electron makes around the nucleus​

Answers

Answered by antiochus
0

Answer:

μn=\sqrt{\frac{ze^{2} }{mr_{n} } )}

Radius of 3rd orbit is=r_{1} *n^{2}

                                  =0.529*10^{-8} *9cm

μn=\sqrt{(\frac{1*(4.083*10^{-10} )^{2} }{(9.108*10^{-28}*0.529*10^{-8}*9  }) }

μn=7.29*10^{7} cmsec^{-1}

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