Question

Calculate the velocity of an electron present in the second excited state of Li^2+ ion

Answer 1

Explanation:

12th

Physics

Dual Nature of Radiation and Matter

Wave Nature of Matter

An electron in an excited s...

PHYSICS

An electron in an excited state of Li

2+

ion has angular momentum 3h/2π. The de Broglie wavelength of the electron in this state in pπα

0

(where α

0

is the Bohr radius). The value of p is :

October 15, 2019

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Gaurika Basant

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VIDEO EXPLANATION

ANSWER

Angular momentum, L=

2π

nh

=

2π

3h

⇒n=3

Also, Wavelengthλ=

p

h

=

mvr

hr

=

2π

3h

hr

=

3

2πr

...(1)

But, r=a

0

Z

n

2

....(2)

Substituting (2) in (1), λ=

3

2π

a

0

Z

n

2

=

3

2π

a

0

3

3

2

=2πa

0

⇒p=2 comparing with the given expression pπa

0