Calculate the velocity of an electron which must be able
to ionize a Li ion in ground state..
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It is important to note that this is Li2+, has an electron configuration of 1s1
Hence, E = -(Z2 / n2) × 1310 kJ/mol = -(32/12) x 1310 kJ/mol = 1.18 × 102 kJ
Hence, E = -(Z2 / n2) × 1310 kJ/mol = -(32/12) x 1310 kJ/mol = 1.18 × 102 kJ
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