Question

calculate the velocity of ejected electron whose kinetic energy is 50*10^-8.

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Answer 1

Answer:

v=✓2KEm

v=✓2×50×10*(-8)×9.1×10*(-31)

✓91×50×2×10^(-50)

= 9.5×10×10^[-20]

Answer 2

Explanation:

Given that, 

vo=7.0×1014s−1

v=1.0×1015s−1

As we know, hv=hv0+21mv2

i.e.  h(v−v0)=K.E.

∴K.E.=(6.626×10−34)×(1.0×1015−7.0×1014)=6.626×10−34×1014(10−7)

∴K.E=19.878×10−20J