Calculate the velocity of projection of a particle so that the maximum height attained by the particle is .5 R, where R is radius of earth.
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Answer:
As we know that
escape velocity =
2gR
So, V=
2
2gR
=
2
gR
=
2R
GM
Now,
Let the maximum height attained be
′
h
′
then an conserving mechanical energy between point of projection and highest point we get.
(h+R)
+GM
+0=0+
2
1
m(
2R
gM
)
2
h+R
1
=
4R
1
3R=h
h=3R
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